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=== Google Interview Self-assessment ===
 * [[BookWiki:geekbang_048_ChenHao_ARTS|陈浩-怎样提升技术领导力]]
 * [[http://www.stochasticgeometry.ie/2010/07/20/interviews-google/||target="_blank"]] My interviews at Google
 * [[https://www.jianshu.com/p/b1f57417320d||target="_blank"]] Google 技术评分卡

==== 11 级技能标准 ====
仔细看了一下，感觉这个标准更适合自己学习的时候使用，面试的技能评估不如 Dreyfus 简单明了。因此增加了对照行。

||<:>'''Level''' ||<:>'''Discription'''||<:>'''与 Dreyfus 技能等级的对照''' ||
|| 0 || you are unfamiliar with the subject area.||新手（Novice） ||
|| 1 || you can read / understand the most fundamental aspects of the subject area.||新手（Novice）+ ||
|| 2 || ability to implement small changes, understand basic principles and able to figure out additional details with minimal help.||新手（Novice）++ ||
|| 3 || basic proficiency in a subject area without relying on help.||高级初学者（Advanced Beginner） ||
|| 4 || you are comfortable with the subject area and all routine work on it:<<BR>><<BR>>'''For software areas''' - ability to develop medium programs using all basic language features w/o book, awareness of more esoteric features (with book).<<BR>>'''For systems areas''' - understanding of many fundamentals of networking and systems administration, ability to run a small network of systems including recovery, debugging and nontrivial troubleshooting that relies on the knowledge of internals. ||高级初学者（Advanced Beginner）+ ||
|| 5 || an even lower degree of reliance on reference materials. Deeper skills in a field or specific technology in the subject area.||高级初学者（Advanced Beginner）++ ||
|| 6 || ability to develop large programs and systems from scratch. Understanding of low level details and internals. Ability to design / deploy most large, distributed systems from scratch.||胜任（competent） ||
|| 7 || you understand and make use of most lesser known language features, technologies, and associated internals. Ability to automate significant amounts of systems administration.||胜任（competent）+ ||
|| 8 || deep understanding of corner cases, esoteric features, protocols and systems including “theory of operation”. Demonstrated ability to design, deploy and own very critical or large infrastructure, build accompanying automation.||精通（Proficient） ||
|| 9 || could have written the book about the subject area but didn’t; works with standards committees on defining new standards and methodologies.||专家(Expert) ||
|| 10|| wrote the book on the subject area (there actually has to be a book). Recognized industry expert in the field, might have invented it.||专家(Expert) + ||
==== Subject Areas ====
 * TCP/IP Networking (OSI stack, DNS etc)
 * Unix/Linux internals
 * Unix/Linux Systems administration
 * Algorithms and Data Structures
 * [[C]]
 * [[CPP|C++]]
 * [[Python]]
 * [[Java]]
 * JavaScript
 * [[Golang|Go]]
 * Shell Scripting (sh, Bash, ksh, csh)
 * SQL and/or Database Admin
 * Scripting language of your choice (not already mentioned) _
 * [[Docker]]
 * People Management
 * Project Management
Line 166: Line 204:
 * [[http://www.ti100.net/html/2013/java_0203/13312.html|亚信Java面试题]]
 * [[http://longzhanfeng1988.blog.163.com/blog/static/3287234020124215465548/|Java中的阻塞和非阻塞IO介绍]]
  * [[http://www.ti100.net/html/2013/java_0203/13312.html|亚信Java面试题|target="_blank"]]
 * [[http://longzhanfeng1988.blog.163.com/blog/static/3287234020124215465548/|Java中的阻塞和非阻塞IO介绍|target="_blank"]]

Back to Human Resource Management

See also Dreyfus 技能获取模型

工程师面试

Contents

  1. 技能评估
    1. Skills Level
    2. Skills
    3. Google Interview Self-assessment
      1. 11 级技能标准
      2. Subject Areas
  2. Java工程师笔试题
    1. 简述sleep()和wait()的区别
    2. 简述以下对象之间的区别
    3. 简述阻塞和非阻塞IO的区别
    4. 内存泄露与内存溢出有什么区别？
    5. 编程序将一个字符串反转
    6. 请补充完成以下单例模式
    7. 给出查询实现方法，评估大致耗时
    8. 用冒泡法重写sort方法
    9. 计算找出这个数组中的哪几个连续的数据之和最大（伪代码即可）
    10. 完成代码，找出未被放入数组中的数字
  3. 参考

1. 技能评估

目的： 了解面试者优势及自我认知评价

方式：

  1. 面试者填写《工程师技能评估表》，为每项技能的自身掌握程度填写等级评估
  2. 面试官据此对其进行相关提问，结合笔试情况二次评估

1.1. Skills Level

  • 新手（Novice）
  • 高级初学者（Advanced Beginner）
  • 胜任（competent）
  • 精通（Proficient）
  • 专家(Expert)

1.2. Skills

  • 需求分析
  • 软件设计
  • 单元测试
  • 数据库
  • 网络通讯
  • Java 语言
  • Bash 脚本
  • Linux 系统

1.3. Google Interview Self-assessment

1.3.1. 11 级技能标准

仔细看了一下，感觉这个标准更适合自己学习的时候使用，面试的技能评估不如 Dreyfus 简单明了。因此增加了对照行。

Level

Discription

与 Dreyfus 技能等级的对照

0

you are unfamiliar with the subject area.

新手（Novice）

1

you can read / understand the most fundamental aspects of the subject area.

新手（Novice）+

2

ability to implement small changes, understand basic principles and able to figure out additional details with minimal help.

新手（Novice）++

3

basic proficiency in a subject area without relying on help.

高级初学者（Advanced Beginner）

4

you are comfortable with the subject area and all routine work on it:

For software areas - ability to develop medium programs using all basic language features w/o book, awareness of more esoteric features (with book).
For systems areas - understanding of many fundamentals of networking and systems administration, ability to run a small network of systems including recovery, debugging and nontrivial troubleshooting that relies on the knowledge of internals.

高级初学者（Advanced Beginner）+

5

an even lower degree of reliance on reference materials. Deeper skills in a field or specific technology in the subject area.

高级初学者（Advanced Beginner）++

6

ability to develop large programs and systems from scratch. Understanding of low level details and internals. Ability to design / deploy most large, distributed systems from scratch.

胜任（competent）

7

you understand and make use of most lesser known language features, technologies, and associated internals. Ability to automate significant amounts of systems administration.

胜任（competent）+

8

deep understanding of corner cases, esoteric features, protocols and systems including “theory of operation”. Demonstrated ability to design, deploy and own very critical or large infrastructure, build accompanying automation.

精通（Proficient）

9

could have written the book about the subject area but didn’t; works with standards committees on defining new standards and methodologies.

专家(Expert)

10

wrote the book on the subject area (there actually has to be a book). Recognized industry expert in the field, might have invented it.

专家(Expert) +

1.3.2. Subject Areas

  • TCP/IP Networking (OSI stack, DNS etc)
  • Unix/Linux internals
  • Unix/Linux Systems administration
  • Algorithms and Data Structures

  • C

  • C++

  • Python

  • Java

  • JavaScript

  • Go

  • Shell Scripting (sh, Bash, ksh, csh)
  • SQL and/or Database Admin
  • Scripting language of your choice (not already mentioned) _

  • Docker

  • People Management
  • Project Management

2. Java工程师笔试题

2.1. 简述sleep()和wait()的区别

~



~

2.2. 简述以下对象之间的区别

ArrayList/Vector?

HashMap/HashTable?

~

2.3. 简述阻塞和非阻塞IO的区别

~



~

2.4. 内存泄露与内存溢出有什么区别？

~

~

2.5. 编程序将一个字符串反转

   1 String str = “Hello, World!”;
   2 ____________________________________________
   3 ____________________________________________
   4 ____________________________________________
   5 ____________________________________________
   6 ____________________________________________
   7 ____________________________________________
   8 ____________________________________________
   9 ____________________________________________
  10 ____________________________________________

2.6. 请补充完成以下单例模式

   1 public class Singleton {
   2         ______  ______   Singleton instance;
   3         ______  Singleton() {
   4                 
   5         }
   6         ______  ______  ______ Singleton getInstance() {
   7                 if(instance==null) {
   8                         instance = new Singleton();
   9                 }
  10                 return instance;
  11         }
  12 }

2.7. 给出查询实现方法，评估大致耗时

有一个100万行的CSV文件 (每个值用逗号分开)，每行有50个字段大约1k的大小，也就是说这是一个1GB大小的文件。
我要统计第七列包含“hello”的一共有多少行，请给出最快的实现方法，并评估大致耗时：
• A - Around 30 seconds to a minute
• B - Around 20-30 seconds
• C - Around 10-15 seconds
• D - Sub 10 seconds

2.8. 用冒泡法重写sort方法

   1 public class Sort {
   2         int[] array = new int[]{1,3,6,8,4,2,5,0,9,7};
   3         public int[] sort() {
   4                 //coding:
   5                 ____________________________________________
   6                 ____________________________________________
   7                 ____________________________________________
   8                 ____________________________________________
   9                 ____________________________________________
  10                 ____________________________________________
  11                 ____________________________________________
  12                 ____________________________________________
  13                 ____________________________________________
  14                 ____________________________________________
  15                 return array;
  16         }

2.9. 计算找出这个数组中的哪几个连续的数据之和最大（伪代码即可）

   1 int [] params = new int[]{12,13,-42,43,-54,91};
   2 ____________________________________________
   3 ____________________________________________
   4 ____________________________________________
   5 ____________________________________________
   6 ____________________________________________
   7 ____________________________________________
   8 ____________________________________________
   9 ____________________________________________
  10 ____________________________________________

2.10. 完成代码，找出未被放入数组中的数字

   1 int [] array = new int[1000];
   2 //把从1到1000的自然数随机拿出999个数字放入array数组中，用最快的方法找出未被放入的数字
   3 ____________________________________________
   4 ____________________________________________
   5 ____________________________________________
   6 ____________________________________________
   7 ____________________________________________
   8 ____________________________________________
   9 ____________________________________________
  10 ____________________________________________
  11 ____________________________________________

3. 参考

MainWiki: EngineerInterview (last edited 2019-08-11 23:00:31 by twotwo)